Thread: Xml Package to get a public Youtube feed

here's a quick XML package to get a public Youtube feed (be aware of namespaces & default namespaces):

Code:

<package displayname="YouTubeFeed" version="2.1" debug="false" includeentityhelper="false">
  <webquery name="youtube" RetType="xml">
    <url>http://gdata.youtube.com/feeds/api/users/{username}/uploads?orderby=updated&amp;max-results={maxResults}</url>
    <querystringreplace replaceTag="{username}" replacetype="request" paramtype="runtime"
      replaceparamname="username" defvalue="molinafinejewelers" validationpattern=""/>
    <querystringreplace replaceTag="{maxResults}" replacetype="request" paramtype="runtime"
      replaceparamname="maxResults" defvalue="3" validationpattern="^\d{1,10}$"/>
  </webquery>
  <PackageTransform>
    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                    xmlns:aspdnsf="urn:aspdnsf"
                    xmlns:atom="http://www.w3.org/2005/Atom"
                    xmlns:media="http://search.yahoo.com/mrss/"
                    xmlns:openSearch="http://a9.com/-/spec/opensearchrss/1.0/"
                    xmlns:gd="http://schemas.google.com/g/2005"
                    xmlns:yt="http://gdata.youtube.com/schemas/2007"
                    exclude-result-prefixes="aspdnsf atom media openSearch gd yt">
      <xsl:output method="html" omit-xml-declaration="yes" />

      <xsl:template match="/">
        <xsl:apply-templates select="/root/youtube/atom:feed/atom:entry" />
      </xsl:template>

      <xsl:template match="atom:entry">

        <div class="entry">
          <a target="_blank" class="imagelink">
            <xsl:attribute name="href" >
              <xsl:value-of select="media:group/media:player/@url" />
            </xsl:attribute>
            <img alt="video" height="90" width="120" >
              <xsl:attribute name="src" >
                <xsl:value-of select="media:group/media:thumbnail[2]/@url" />
              </xsl:attribute>
            </img>
          </a>
          <p>
            <a target="_blank" class="titlelink">
              <xsl:attribute name="href" >
                <xsl:value-of select="media:group/media:player/@url" />
              </xsl:attribute>
              <xsl:value-of select="aspdnsf:GetMLValue(atom:title)" />
            </a>
            <br />by&#160;<a target="_blank" class="authorlink">
              <xsl:attribute name="href" >
                <xsl:value-of select="concat('http://www.youtube.com/user/', atom:author/atom:name)" />
              </xsl:attribute>
              <xsl:value-of select="aspdnsf:GetMLValue(atom:author/atom:name)" />
            </a>
            <br />views&#160;<xsl:value-of select="yt:statistics/@viewCount" />
          </p>
        </div>

      </xsl:template>
    </xsl:stylesheet>

  </PackageTransform>
</package>

How can we alter this xml package so the thumbnails actually link to the videos on the channel / profile page?

as far as I know, you can't link directly to a video on a channel/profile page - the video thumbnails in this package actually link to the video in a standard YouTube player - the profile name links to the channel/profile page.

for a development example see - http://molina-aspdotnetstorefront.st...e-social-scene

bottom left section

actually if you want to link to the channel/profile page - you'll need to simply compose links similar to http://www.youtube.com/user/molinafi.../0/nHpiZpEQFTY

You'll have to dig through the API docs on how to generate these links